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- Equation:
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Equation 2*x^2+5*x-12=0
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Identical expressions
- two *x^ two + five *x- twelve = zero
- 2 multiply by x squared plus 5 multiply by x minus 12 equally 0
- two multiply by x to the power of two plus five multiply by x minus twelve equally zero
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Similar expressions
- 2*x^2-5*x-12=0
- 2*x^2+5*x+12=0
2*x^2+5*x-12=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 2$$
$$b = 5$$
$$c = -12$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = \frac{3}{2}$$
$$x_{2} = -4$$
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 2$$
$$b = 5$$
$$c = -12$$
, then
D = b^2 - 4 * a * c =
(5)^2 - 4 * (2) * (-12) = 121
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = \frac{3}{2}$$
$$x_{2} = -4$$
Vieta's Theorem
rewrite the equation
$$\left(2 x^{2} + 5 x\right) - 12 = 0$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} + \frac{5 x}{2} - 6 = 0$$
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = \frac{5}{2}$$
$$q = \frac{c}{a}$$
$$q = -6$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = - \frac{5}{2}$$
$$x_{1} x_{2} = -6$$
$$\left(2 x^{2} + 5 x\right) - 12 = 0$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} + \frac{5 x}{2} - 6 = 0$$
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = \frac{5}{2}$$
$$q = \frac{c}{a}$$
$$q = -6$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = - \frac{5}{2}$$
$$x_{1} x_{2} = -6$$
Sum and product of roots
[src]
sum
-4 + 3/2
$$-4 + \frac{3}{2}$$
=
-5/2
$$- \frac{5}{2}$$
product
-4*3 ---- 2
$$- 6$$
=
-6
$$-6$$
-6
The graph