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Similar expressions
- (2*x-8)^2=0
(2*x+8)^2=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Expand the expression in the equation
$$\left(2 x + 8\right)^{2} = 0$$
We get the quadratic equation
$$4 x^{2} + 32 x + 64 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 4$$
$$b = 32$$
$$c = 64$$
, then
Because D = 0, then the equation has one root.
$$x_{1} = -4$$
$$\left(2 x + 8\right)^{2} = 0$$
We get the quadratic equation
$$4 x^{2} + 32 x + 64 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 4$$
$$b = 32$$
$$c = 64$$
, then
D = b^2 - 4 * a * c =
(32)^2 - 4 * (4) * (64) = 0
Because D = 0, then the equation has one root.
x = -b/2a = -32/2/(4)
$$x_{1} = -4$$
The graph