Mister Exam
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How to use it?
- Equation:
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Equation ((1/5))^(x)^(2)*5^(2*x+2)=(1/5)^(6)
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Equation x^3-x^2-x-1=0
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Equation -x=3
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Equation x-6/2-x/3=3
- Express {x} in terms of y where:
- 9*x+10*y=5
- -4*x+19*y=-13
- -5*x-6*y=-1
- -7*x+15*y=18
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Identical expressions
- x- six / two -x/ three = three
- x minus 6 divide by 2 minus x divide by 3 equally 3
- x minus six divide by two minus x divide by three equally three
- x-6 divide by 2-x divide by 3=3
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Similar expressions
- (x-6)/2-x/3=3
- x+6/2-x/3=3
- x-6/2+x/3=3
x-6/2-x/3=3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$\frac{2 x}{3} = 6$$
Divide both parts of the equation by 2/3
We get the answer: x = 9
x-6/2-x/3 = 3
Looking for similar summands in the left part:
-3 + 2*x/3 = 3
Move free summands (without x)
from left part to right part, we given:
$$\frac{2 x}{3} = 6$$
Divide both parts of the equation by 2/3
x = 6 / (2/3)
We get the answer: x = 9
The graph