(2-c)+3(c-3)=-12 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
(2-c)+3*(c-3) = -12
Expand brackets in the left part
2-c+3*c-3*3 = -12
Looking for similar summands in the left part:
-7 + 2*c = -12
Move free summands (without c)
from left part to right part, we given:
$$2 c = -5$$
Divide both parts of the equation by 2
c = -5 / (2)
We get the answer: c = -5/2
$$c_{1} = - \frac{5}{2}$$
Sum and product of roots
[src]
$$- \frac{5}{2}$$
$$- \frac{5}{2}$$
$$- \frac{5}{2}$$
$$- \frac{5}{2}$$