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24t^2-(6t-4)×(4t+1) equation

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Numerical solution:

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The solution

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    2                          
24*t  - (6*t - 4)*(4*t + 1) = 0
$$24 t^{2} - \left(4 t + 1\right) \left(6 t - 4\right) = 0$$
Detail solution
Given the equation:
24*t^2-(6*t-4)*(4*t+1) = 0

Expand expressions:
24*t^2 + 4 - 24*t^2 + 10*t = 0

Reducing, you get:
4 + 10*t = 0

Move free summands (without t)
from left part to right part, we given:
$$10 t = -4$$
Divide both parts of the equation by 10
t = -4 / (10)

We get the answer: t = -2/5
The graph
Sum and product of roots [src]
sum
-2/5
$$- \frac{2}{5}$$
=
-2/5
$$- \frac{2}{5}$$
product
-2/5
$$- \frac{2}{5}$$
=
-2/5
$$- \frac{2}{5}$$
-2/5
Rapid solution [src]
t1 = -2/5
$$t_{1} = - \frac{2}{5}$$
t1 = -2/5
Numerical answer [src]
t1 = -0.4
t1 = -0.4