24t^2-(6t-4)×(4t+1) equation
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The solution
Detail solution
Given the equation:
24*t^2-(6*t-4)*(4*t+1) = 0
Expand expressions:
24*t^2 + 4 - 24*t^2 + 10*t = 0
Reducing, you get:
4 + 10*t = 0
Move free summands (without t)
from left part to right part, we given:
$$10 t = -4$$
Divide both parts of the equation by 10
t = -4 / (10)
We get the answer: t = -2/5
Sum and product of roots
[src]
$$- \frac{2}{5}$$
$$- \frac{2}{5}$$
$$- \frac{2}{5}$$
$$- \frac{2}{5}$$
$$t_{1} = - \frac{2}{5}$$