12*y+3=0 equation
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The solution
Detail solution
Given the linear equation:
12*y+3 = 0
Move free summands (without y)
from left part to right part, we given:
$$12 y = -3$$
Divide both parts of the equation by 12
y = -3 / (12)
We get the answer: y = -1/4
$$y_{1} = - \frac{1}{4}$$
Sum and product of roots
[src]
$$- \frac{1}{4}$$
$$- \frac{1}{4}$$
$$- \frac{1}{4}$$
$$- \frac{1}{4}$$