Mister Exam

12y+3y+20y-9y equation

The teacher will be very surprised to see your correct solution 😉

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Numerical solution:

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The solution

You have entered [src]
12*y + 3*y + 20*y - 9*y = 0
$$- 9 y + \left(20 y + \left(3 y + 12 y\right)\right) = 0$$
Detail solution
Given the linear equation:
12*y+3*y+20*y-9*y = 0

Looking for similar summands in the left part:
26*y = 0

Divide both parts of the equation by 26
y = 0 / (26)

We get the answer: y = 0
The graph
Sum and product of roots [src]
sum
0
$$0$$
=
0
$$0$$
product
0
$$0$$
=
0
$$0$$
0
Rapid solution [src]
y1 = 0
$$y_{1} = 0$$
y1 = 0
Numerical answer [src]
y1 = 0.0
y1 = 0.0