Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 25*x^2=16
- Equation 3*x^2-48=0
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Equation x^2-5*x+7=0
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Equation x^2-20=0
- Express {x} in terms of y where:
- 1*x+11*y=-3
- 10*x+3*y=2
- -20*x+14*y=16
- 15*x-3*y=19
- Sum of series:
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6/7
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Identical expressions
- twelve /x+ three = six / seven
- 12 divide by x plus 3 equally 6 divide by 7
- twelve divide by x plus three equally six divide by seven
- 12 divide by x+3=6 divide by 7
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Similar expressions
- (3*x-16)/(7*x-3)+(9+3*x)/(7*x+4)=1
- (x^2-x)/(x+3)=12/(x+3)
- 0.3193=(y-4.46)/(7.58-4.46)
- (36/(9+x))+(16/(7+x))=5
- -4,6-1,5(4x-5)+8,5x=0.3(3x-7)+(2x-15.6)/7
- (x^2-x-12)/(x+3)=0
- 12/x-3=6/7
12/x+3=6/7 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$3 + \frac{12}{x} = \frac{6}{7}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
so we get the equation
$$- \frac{x}{12} = \frac{7}{15}$$
$$- \frac{x}{12} = \frac{7}{15}$$
Divide both parts of the equation by -1/12
We get the answer: x = -28/5
$$3 + \frac{12}{x} = \frac{6}{7}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 1
b1 = 7/15
a2 = 1
b2 = -x/12
so we get the equation
$$- \frac{x}{12} = \frac{7}{15}$$
$$- \frac{x}{12} = \frac{7}{15}$$
Divide both parts of the equation by -1/12
x = 7/15 / (-1/12)
We get the answer: x = -28/5
Sum and product of roots
[src]
sum
-28/5
$$- \frac{28}{5}$$
=
-28/5
$$- \frac{28}{5}$$
product
-28/5
$$- \frac{28}{5}$$
=
-28/5
$$- \frac{28}{5}$$
-28/5