Mister Exam
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- Equation:
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Equation x*8=25+15
- Equation (x-4)^4-4*(x-4)^2-21=0
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Equation ((1/5))^(x)^(2)*5^(2*x+2)=(1/5)^(6)
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Equation x-2=0
- Express {x} in terms of y where:
- 15*x-5*y=-5
- 15*x+7*y=2
- 12*x-20*y=10
- -11*x-1*y=15
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Identical expressions
- twelve /(x+ three)=- six / seven
- 12 divide by (x plus 3) equally minus 6 divide by 7
- twelve divide by (x plus three) equally minus six divide by seven
- 12/x+3=-6/7
- 12 divide by (x+3)=-6 divide by 7
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Similar expressions
- 12/(x-3)=-6/7
- (x-1)^2/(x+3)=0
- 12/(x+3)=+6/7
- (x-12)/(x+3)=0
- 12/x+3=6/7
- (x^2+4x-12)/(x+3)=0
12/(x+3)=-6/7 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{12}{x + 3} = - \frac{6}{7}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
so we get the equation
$$\frac{\left(-7\right) 12}{6} = x + 3$$
$$-14 = x + 3$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x + 17$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 17$$
Divide both parts of the equation by -1
We get the answer: x = -17
$$\frac{12}{x + 3} = - \frac{6}{7}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 12
b1 = 3 + x
a2 = 1
b2 = -7/6
so we get the equation
$$\frac{\left(-7\right) 12}{6} = x + 3$$
$$-14 = x + 3$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x + 17$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 17$$
Divide both parts of the equation by -1
x = 17 / (-1)
We get the answer: x = -17
The graph