Mister Exam
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How to use it?
- Equation:
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Equation 3*x^2-x-5=0
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Equation 3x+3=-2-7x
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Equation 2x^2+6x=0
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Equation 5x-3=2x
- Express {x} in terms of y where:
- -1*x+4*y=5
- -14*x-10*y=-1
- 12*x-1*y=-19
- -8*x-16*y=-20
- Derivative of:
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3x+3
- Canonical form:
- 3x+3
- Graphing y =:
- 3x+3
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Identical expressions
- three x+3=- two -7x
- 3x plus 3 equally minus 2 minus 7x
- three x plus 3 equally minus two minus 7x
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Similar expressions
- 7^x-2-7^x=336
- 3x+3=-2+7x
- 3x-3=-2-7x
- (2*x+9)^1/2-2-(7*x+2)^1/2=0
- 3^x+3^3-x=12
- x^3-3*x+3=0
- -6*3^x+3^(2x)=27
- 3x+3=+2-7x
3x+3=-2-7x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$3 x = - 7 x - 5$$
Move the summands with the unknown x
from the right part to the left part:
$$10 x = -5$$
Divide both parts of the equation by 10
We get the answer: x = -1/2
3*x+3 = -2-7*x
Move free summands (without x)
from left part to right part, we given:
$$3 x = - 7 x - 5$$
Move the summands with the unknown x
from the right part to the left part:
$$10 x = -5$$
Divide both parts of the equation by 10
x = -5 / (10)
We get the answer: x = -1/2
Sum and product of roots
[src]
sum
-1/2
$$- \frac{1}{2}$$
=
-1/2
$$- \frac{1}{2}$$
product
-1/2
$$- \frac{1}{2}$$
=
-1/2
$$- \frac{1}{2}$$
-1/2
The graph