(3x-2)(3x+4)=3(x+1)(3x+1) equation
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The solution
Detail solution
Given the equation:
(3*x-2)*(3*x+4) = 3*(x+1)*(3*x+1)
Expand expressions:
-8 + 6*x + 9*x^2 = 3*(x+1)*(3*x+1)
(3*x-2)*(3*x+4) = 3 + 9*x^2 + 12*x
Reducing, you get:
-11 - 6*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 6 x = 11$$
Divide both parts of the equation by -6
x = 11 / (-6)
We get the answer: x = -11/6
Sum and product of roots
[src]
$$- \frac{11}{6}$$
$$- \frac{11}{6}$$
$$- \frac{11}{6}$$
$$- \frac{11}{6}$$
$$x_{1} = - \frac{11}{6}$$