Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation cos(x)=5
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Equation x+970=69*32
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Equation x^3+x^2=0
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Equation 6*x^2+x-1=0
- Express {x} in terms of y where:
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- 15*x-5*y=-5
- 6*x+7*y=-10
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Identical expressions
- three √x- ten = six
- 3√x minus 10 equally 6
- three √x minus ten equally six
-
Similar expressions
- 3√x+10=6
3√x-10=6 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$3 \sqrt{x} - 10 = 6$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$3^{2} \left(\sqrt{x}\right)^{2} = 16^{2}$$
or
$$9 x = 256$$
Divide both parts of the equation by 9
We get the answer: x = 256/9
The final answer:
$$x_{1} = \frac{256}{9}$$
$$3 \sqrt{x} - 10 = 6$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$3^{2} \left(\sqrt{x}\right)^{2} = 16^{2}$$
or
$$9 x = 256$$
Divide both parts of the equation by 9
x = 256 / (9)
We get the answer: x = 256/9
The final answer:
$$x_{1} = \frac{256}{9}$$
Sum and product of roots
[src]
sum
256/9
$$\frac{256}{9}$$
=
256/9
$$\frac{256}{9}$$
product
256/9
$$\frac{256}{9}$$
=
256/9
$$\frac{256}{9}$$
256/9