Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation 5/6*x+16=4/9*x+9
-
Equation 5x^2-x-6=0
-
Equation (x+9)/7-x/2=2
-
Equation 3(x-1)+x=2x
- Express {x} in terms of y where:
- 18*x-16*y=-11
- -7*x+20*y=-2
- 3*x-2*y=-14
- -19*x-4*y=5
- Integral of d{x}:
-
2x
- Graphing y =:
- 2x
- Derivative of:
-
2x
-
Identical expressions
- three (x- one)+x=2x
- 3(x minus 1) plus x equally 2x
- three (x minus one) plus x equally 2x
- 3x-1+x=2x
-
Similar expressions
- 32*x=2
- 3(x-1)-x=2x
- (x+1)*(3*x-1)+(x+7)*(x-7)=4-2*x^2
- x^(2)*3^(x-1)+x((3^(x))-(2^(x)))=2(2^x-(3^x-1))
- 2^4-2*x=64
- 2*(x+3)=12
- 3(x+1)+x=2x
- x^2*3^x-1+x(3^x-2^x)=2(2^x-3^x-1)
3(x-1)+x=2x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$4 x = 2 x + 3$$
Move the summands with the unknown x
from the right part to the left part:
$$2 x = 3$$
Divide both parts of the equation by 2
We get the answer: x = 3/2
3*(x-1)+x = 2*x
Expand brackets in the left part
3*x-3*1+x = 2*x
Looking for similar summands in the left part:
-3 + 4*x = 2*x
Move free summands (without x)
from left part to right part, we given:
$$4 x = 2 x + 3$$
Move the summands with the unknown x
from the right part to the left part:
$$2 x = 3$$
Divide both parts of the equation by 2
x = 3 / (2)
We get the answer: x = 3/2
Sum and product of roots
[src]
sum
3/2
$$\frac{3}{2}$$
=
3/2
$$\frac{3}{2}$$
product
3/2
$$\frac{3}{2}$$
=
3/2
$$\frac{3}{2}$$
3/2
The graph