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3(2-3x)+20+3x=2

3(2-3x)+20+3x=2 equation

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Numerical solution:

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The solution

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3*(2 - 3*x) + 20 + 3*x = 2
$$3 x + \left(3 \left(2 - 3 x\right) + 20\right) = 2$$
Detail solution
Given the linear equation:
3*(2-3*x)+20+3*x = 2

Expand brackets in the left part
3*2-3*3*x+20+3*x = 2

Looking for similar summands in the left part:
26 - 6*x = 2

Move free summands (without x)
from left part to right part, we given:
$$- 6 x = -24$$
Divide both parts of the equation by -6
x = -24 / (-6)

We get the answer: x = 4
The graph
Sum and product of roots [src]
sum
4
$$4$$
=
4
$$4$$
product
4
$$4$$
=
4
$$4$$
4
Rapid solution [src]
x1 = 4
$$x_{1} = 4$$
x1 = 4
Numerical answer [src]
x1 = 4.0
x1 = 4.0
The graph
3(2-3x)+20+3x=2 equation