Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (x+10)^2=(2-x)^2
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Equation -7-x=3x+17
- Equation 3(2,4-1,1m)=2.7m+3.2
- Equation (x^2+4x)^2=(x+6)(2-x)
- Express {x} in terms of y where:
- -4*x-11*y=6
- 5*x-3*y=1
- -16*x-6*y=-19
- -7*x+12*y=-8
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Identical expressions
- three (two , four - one ,1m)= two .7m+ three . two
- 3(2,4 minus 1,1m) equally 2.7m plus 3.2
- three (two , four minus one ,1m) equally two .7m plus three . two
- 32,4-1,1m=2.7m+3.2
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Similar expressions
- 3(2,4-1,1m)=2.7m-3.2
- 3(2,4+1,1m)=2.7m+3.2
3(2,4-1,1m)=2.7m+3.2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
/12 11*m\ 27*m 16 3*|-- - ----| = ---- + -- \5 10 / 10 5
$$3 \left(\frac{12}{5} - \frac{11 m}{10}\right) = \frac{27 m}{10} + \frac{16}{5}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without m)
from left part to right part, we given:
$$- \frac{33 m}{10} = \frac{27 m}{10} - 4$$
Move the summands with the unknown m
from the right part to the left part:
$$\left(-6\right) m = -4$$
Divide both parts of the equation by -6
We get the answer: m = 2/3
3*((12/5)-(11/10)*m) = (27/10)*m+(16/5)
Expand brackets in the left part
3*12/5-11/10m) = (27/10)*m+(16/5)
Expand brackets in the right part
3*12/5-11/10m) = 27/10m+16/5
Move free summands (without m)
from left part to right part, we given:
$$- \frac{33 m}{10} = \frac{27 m}{10} - 4$$
Move the summands with the unknown m
from the right part to the left part:
$$\left(-6\right) m = -4$$
Divide both parts of the equation by -6
m = -4 / (-6)
We get the answer: m = 2/3
Sum and product of roots
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sum
2/3
$$\frac{2}{3}$$
=
2/3
$$\frac{2}{3}$$
product
2/3
$$\frac{2}{3}$$
=
2/3
$$\frac{2}{3}$$
2/3