3^x=2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$3^{x} = 2$$
or
$$3^{x} - 2 = 0$$
or
$$3^{x} = 2$$
or
$$3^{x} = 2$$
- this is the simplest exponential equation
Do replacement
$$v = 3^{x}$$
we get
$$v - 2 = 0$$
or
$$v - 2 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 2$$
We get the answer: v = 2
do backward replacement
$$3^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(3 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(2 \right)}}{\log{\left(3 \right)}} = \frac{\log{\left(2 \right)}}{\log{\left(3 \right)}}$$
Sum and product of roots
[src]
$$\frac{\log{\left(2 \right)}}{\log{\left(3 \right)}}$$
$$\frac{\log{\left(2 \right)}}{\log{\left(3 \right)}}$$
$$\frac{\log{\left(2 \right)}}{\log{\left(3 \right)}}$$
$$\frac{\log{\left(2 \right)}}{\log{\left(3 \right)}}$$
log(2)
x1 = ------
log(3)
$$x_{1} = \frac{\log{\left(2 \right)}}{\log{\left(3 \right)}}$$