3^x=-3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$3^{x} = -3$$
or
$$3^{x} + 3 = 0$$
or
$$3^{x} = -3$$
or
$$3^{x} = -3$$
- this is the simplest exponential equation
Do replacement
$$v = 3^{x}$$
we get
$$v + 3 = 0$$
or
$$v + 3 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = -3$$
We get the answer: v = -3
do backward replacement
$$3^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(3 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(-3 \right)}}{\log{\left(3 \right)}} = 1 + \frac{i \pi}{\log{\left(3 \right)}}$$
pi*I
x1 = 1 + ------
log(3)
$$x_{1} = 1 + \frac{i \pi}{\log{\left(3 \right)}}$$
Sum and product of roots
[src]
$$1 + \frac{i \pi}{\log{\left(3 \right)}}$$
$$1 + \frac{i \pi}{\log{\left(3 \right)}}$$
$$1 + \frac{i \pi}{\log{\left(3 \right)}}$$
$$1 + \frac{i \pi}{\log{\left(3 \right)}}$$
x1 = 1.0 + 2.85960086738013*i
x1 = 1.0 + 2.85960086738013*i