Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2x-3=10
-
Equation 2*sin(x)=0
-
Equation 4*x=-12
-
Equation x^4-x^2+1=0
- Express {x} in terms of y where:
- -12*x-6*y=-3
- -7*x-11*y=18
- -13*x+8*y=-18
- -13*x+3*y=-4
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Identical expressions
- three , nine -6x+ two ,1x- four , five = zero
- 3,9 minus 6x plus 2,1x minus 4,5 equally 0
- three , nine minus 6x plus two ,1x minus four , five equally zero
- 3,9-6x+2,1x-4,5=O
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Similar expressions
- 3,9+6x+2,1x-4,5=0
- 3,9-6x+2,1x+4,5=0
- 3,9-6x-2,1x-4,5=0
3,9-6x+2,1x-4,5=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
39 21*x 9 -- - 6*x + ---- - - = 0 10 10 2
$$\left(\frac{21 x}{10} + \left(\frac{39}{10} - 6 x\right)\right) - \frac{9}{2} = 0$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- \frac{39 x}{10} = \frac{3}{5}$$
Divide both parts of the equation by -39/10
We get the answer: x = -2/13
(39/10)-6*x+(21/10)*x-(9/2) = 0
Expand brackets in the left part
39/10-6*x+21/10x-9/2 = 0
Looking for similar summands in the left part:
-3/5 - 39*x/10 = 0
Move free summands (without x)
from left part to right part, we given:
$$- \frac{39 x}{10} = \frac{3}{5}$$
Divide both parts of the equation by -39/10
x = 3/5 / (-39/10)
We get the answer: x = -2/13
Sum and product of roots
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sum
-2/13
$$- \frac{2}{13}$$
=
-2/13
$$- \frac{2}{13}$$
product
-2/13
$$- \frac{2}{13}$$
=
-2/13
$$- \frac{2}{13}$$
-2/13