Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation x^2=-7
- Equation 3*t+y=16
- Equation 25x=-
- Equation 5+×=16
- Express {x} in terms of y where:
- -11*x+9*y=-10
- -4*x+11*y=13
- 3*x-12*y=15
- -4*x-7*y=6
- Sum of series:
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16
- Derivative of:
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16
- Integral of d{x}:
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16
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Identical expressions
- three *t+y= sixteen
- 3 multiply by t plus y equally 16
- three multiply by t plus y equally sixteen
- 3t+y=16
-
Similar expressions
- 3*t-y=16
3*t+y=16 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$y = 16 - 3 t$$
We get the answer: y = 16 - 3*t
3*t+y = 16
Looking for similar summands in the left part:
y + 3*t = 16
Move the summands with the other variables
from left part to right part, we given:
$$y = 16 - 3 t$$
We get the answer: y = 16 - 3*t
The graph
Sum and product of roots
[src]
sum
16 - 3*re(t) - 3*I*im(t)
$$- 3 \operatorname{re}{\left(t\right)} - 3 i \operatorname{im}{\left(t\right)} + 16$$
=
16 - 3*re(t) - 3*I*im(t)
$$- 3 \operatorname{re}{\left(t\right)} - 3 i \operatorname{im}{\left(t\right)} + 16$$
product
16 - 3*re(t) - 3*I*im(t)
$$- 3 \operatorname{re}{\left(t\right)} - 3 i \operatorname{im}{\left(t\right)} + 16$$
=
16 - 3*re(t) - 3*I*im(t)
$$- 3 \operatorname{re}{\left(t\right)} - 3 i \operatorname{im}{\left(t\right)} + 16$$
16 - 3*re(t) - 3*i*im(t)
Rapid solution
[src]
y1 = 16 - 3*re(t) - 3*I*im(t)
$$y_{1} = - 3 \operatorname{re}{\left(t\right)} - 3 i \operatorname{im}{\left(t\right)} + 16$$
y1 = -3*re(t) - 3*i*im(t) + 16