Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation sin(x)=1/5
-
Equation x^2+11=0
-
Equation x^2+5x+6=0
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Equation -x/7+x=15/7
- Express {x} in terms of y where:
- 9*x+17*y=13
- 20*x+18*y=-9
- -4*x-8*y=-20
- -1*x+4*y=-10
- Integral of d{x}:
- (2x-1)/2
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Identical expressions
- (three -x)/ three =(two x- one)/2
- (3 minus x) divide by 3 equally (2x minus 1) divide by 2
- (three minus x) divide by three equally (two x minus one) divide by 2
- 3-x/3=2x-1/2
- (3-x) divide by 3=(2x-1) divide by 2
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Similar expressions
- 3-x/3=x/2
- (3-x)/3=(2x+1)/2
- 2sin2x-1/2=1
- 2/3(1*1/2x+3/5)-4/5(5/12x-1/2)=1*3/5
- x-1/x+2=2x-1/2x+1
- (2*sqrt(3-x)+(2*x-7)/(2*sqrt(3-x)))/(3-x)=0
- 353-x/353+x/2/(467/25)+(16067/1000)=0
- (((x^3)*(3-x))/((3-x)*2*(1-x)))*35.53=1.10*10^37
- (3+x)/3=(2x-1)/2
(3-x)/3=(2x-1)/2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$- \frac{x}{3} = x - \frac{3}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-4\right) x}{3} = - \frac{3}{2}$$
Divide both parts of the equation by -4/3
We get the answer: x = 9/8
(3-x)/3 = (2*x-1)/2
Expand brackets in the left part
3/3-x/3 = (2*x-1)/2
Expand brackets in the right part
3/3-x/3 = 2*x/2-1/2
Move free summands (without x)
from left part to right part, we given:
$$- \frac{x}{3} = x - \frac{3}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-4\right) x}{3} = - \frac{3}{2}$$
Divide both parts of the equation by -4/3
x = -3/2 / (-4/3)
We get the answer: x = 9/8
Sum and product of roots
[src]
sum
9/8
$$\frac{9}{8}$$
=
9/8
$$\frac{9}{8}$$
product
9/8
$$\frac{9}{8}$$
=
9/8
$$\frac{9}{8}$$
9/8