Mister Exam
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How to use it?
- Equation:
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Equation x^2+9=(x+9)^2
-
Equation -x=4-3(3x-8)
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Equation 9x-7=6x+14
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Equation x+3=-9*x
- Express {x} in terms of y where:
- -18*x-1*y=-11
- 1*x-6*y=-19
- -1*x-20*y=-17
- 7*x+13*y=-13
- Derivative of:
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x/3
- Integral of d{x}:
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x/3
- Graphing y =:
- x/3
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Identical expressions
- three -x/ seven =x/ three
- 3 minus x divide by 7 equally x divide by 3
- three minus x divide by seven equally x divide by three
- 3-x divide by 7=x divide by 3
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Similar expressions
- ((x+9)/3)-(x/7)=2
- arcsin(x)/3=pi
- 3+x/7=x/3
3-x/7=x/3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- \frac{x}{7} = \frac{x}{3} - 3$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-10\right) x}{21} = -3$$
Divide both parts of the equation by -10/21
We get the answer: x = 63/10
3-x/7 = x/3
Move free summands (without x)
from left part to right part, we given:
$$- \frac{x}{7} = \frac{x}{3} - 3$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-10\right) x}{21} = -3$$
Divide both parts of the equation by -10/21
x = -3 / (-10/21)
We get the answer: x = 63/10
Sum and product of roots
[src]
sum
63 -- 10
$$\frac{63}{10}$$
=
63 -- 10
$$\frac{63}{10}$$
product
63 -- 10
$$\frac{63}{10}$$
=
63 -- 10
$$\frac{63}{10}$$
63/10
The graph