Mister Exam
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- Equation:
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Equation x^2+3x+2=0
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Equation z^2-6*z+10=0
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Equation x^2+5x+6=0
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Equation 5x+12=8x+30
- Express {x} in terms of y where:
- -20*x-6*y=4
- -13*x+7*y=-15
- 5*x-14*y=-15
- -12*x-10*y=-16
- Graphing y =:
- 3-5*(x+1)
- Limit of the function:
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6-4*x
- Derivative of:
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6-4*x
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Identical expressions
- three - five *(x+ one)= six - four *x
- 3 minus 5 multiply by (x plus 1) equally 6 minus 4 multiply by x
- three minus five multiply by (x plus one) equally six minus four multiply by x
- 3-5(x+1)=6-4x
- 3-5x+1=6-4x
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Similar expressions
- 3+5*(x+1)=6-4*x
- 3-5*(x-1)=6-4*x
- sqrt5(26-4x)=2
- ((2x+3)/3)-((5x+13)/6)+(5-2x)/2=6
- 0,4×(6-4x)=0,5×(7-3x)-1,9
- f*x=(3*x^4-4*x^3-5*x+12)/x
- (3x-1)*(6-4x)=0
- 3-5(x+1)=9-4x
- 3-5*(x+1)=6+4*x
- (2*x+3)/3-(5*x+13)/6+(5-2*x)/2=6
3-5*(x+1)=6-4*x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = 8 - 4 x$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 8$$
Divide both parts of the equation by -1
We get the answer: x = -8
3-5*(x+1) = 6-4*x
Expand brackets in the left part
3-5*x-5*1 = 6-4*x
Looking for similar summands in the left part:
-2 - 5*x = 6-4*x
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = 8 - 4 x$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 8$$
Divide both parts of the equation by -1
x = 8 / (-1)
We get the answer: x = -8
The graph