sqrt5(26-4x)=2 equation
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The solution
Detail solution
Given the equation
$$\left(26 - 4 x\right)^{0.2} = 2$$
Because equation degree is equal to = 0.2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 5-th degree:
We get:
$$\left(\left(26 - 4 x\right)^{0.2}\right)^{5} = 2^{5}$$
or
$$26 - 4 x = 32$$
Move free summands (without x)
from left part to right part, we given:
$$- 4 x = 6$$
Divide both parts of the equation by -4
x = 6 / (-4)
We get the answer: x = -1.5
The final answer:
$$x_{1} = -1.5$$
Sum and product of roots
[src]
$$-1.5$$
$$-1.5$$
$$-1.5$$
$$-1.5$$
x2 = -1.5 + 2.96369604345652e-18*i
x3 = -1.50000000000029 + 6.45685164408499e-13*i
x3 = -1.50000000000029 + 6.45685164408499e-13*i