Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation cos(x)=1/3
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Equation sin5x-√3cos5x=0
- Equation (√x-6)(2x^2-x-15)=0
- Equation Cos3xcos5x-sin3xsin5x=0
- Express {x} in terms of y where:
- -11*x+4*y=-8
- -14*x+1*y=3
- 14*x+16*y=14
- 16*x+7*y=8
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Identical expressions
- √ three ctgx+3= zero
- √3ctgx plus 3 equally 0
- √ three ctgx plus 3 equally zero
- √3ctgx+3=O
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Similar expressions
- √3ctgx-3=0
√3ctgx+3=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$\sqrt{3 \cot{\left(x \right)}} + 3 = 0$$
transform
$$\sqrt{3} \sqrt{\cot{\left(x \right)}} + 3 = 0$$
$$\sqrt{3 \cot{\left(x \right)}} + 3 = 0$$
Do replacement
$$w = \cot{\left(x \right)}$$
Given the equation
$$\sqrt{3} \sqrt{w} + 3 = 0$$
Because equation degree is equal to = 1/2 and the free term = -3 < 0,
so the real solutions of the equation d'not exist
do backward replacement
$$\cot{\left(x \right)} = w$$
substitute w:
$$\sqrt{3 \cot{\left(x \right)}} + 3 = 0$$
transform
$$\sqrt{3} \sqrt{\cot{\left(x \right)}} + 3 = 0$$
$$\sqrt{3 \cot{\left(x \right)}} + 3 = 0$$
Do replacement
$$w = \cot{\left(x \right)}$$
Given the equation
$$\sqrt{3} \sqrt{w} + 3 = 0$$
Because equation degree is equal to = 1/2 and the free term = -3 < 0,
so the real solutions of the equation d'not exist
do backward replacement
$$\cot{\left(x \right)} = w$$
substitute w: