Mister Exam
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How to use it?
- Equation:
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Equation 4-6*(x+2)=3-5*x
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Equation 1/(x-3)^2-3/(x-3)-4=0
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Equation 2-3(7+2x)=11
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Equation x^2-2x+1=0
- Express {x} in terms of y where:
- 17*x-20*y=6
- 5*x-13*y=17
- 6*x+17*y=3
- 1*x+4*y=20
- Derivative of:
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6x
- Integral of d{x}:
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6x
- Canonical form:
- 6x
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Identical expressions
- thirteen -(5x+ eleven)=6x
- 13 minus (5x plus 11) equally 6x
- thirteen minus (5x plus eleven) equally 6x
- 13-5x+11=6x
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Similar expressions
- 3log16((x^2+1)^2+x)+log2((x^2+1)^2-x)=log16(4x+1)-0,5
- 4-6*(x+2)=3-5*x
- 13-(5x-11)=6x
- 13+(5x+11)=6x
- -12568,2*exp(-1557,4*x)+76201,8*exp(-9442,6*x)=0
13-(5x+11)=6x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = 6 x - 2$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-11\right) x = -2$$
Divide both parts of the equation by -11
We get the answer: x = 2/11
13-(5*x+11) = 6*x
Expand brackets in the left part
13-5*x-11 = 6*x
Looking for similar summands in the left part:
2 - 5*x = 6*x
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = 6 x - 2$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-11\right) x = -2$$
Divide both parts of the equation by -11
x = -2 / (-11)
We get the answer: x = 2/11
Sum and product of roots
[src]
sum
2/11
$$\frac{2}{11}$$
=
2/11
$$\frac{2}{11}$$
product
2/11
$$\frac{2}{11}$$
=
2/11
$$\frac{2}{11}$$
2/11
The graph