Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 0*x=0
-
Equation x^2=0
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Equation sin(x)=-√3/2
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Equation (x+10)(-x-8)=0
- Express {x} in terms of y where:
- 18*x+14*y=-11
- -5*x+6*y=19
- 4*x+16*y=6
- -6*x+1*y=14
-
Identical expressions
- tg(x/ three -pi/ six)=sqr(three)
- tg(x divide by 3 minus Pi divide by 6) equally sqr(3)
- tg(x divide by three minus Pi divide by six) equally sqr(three)
- tgx/3-pi/6=sqr3
- tg(x divide by 3-pi divide by 6)=sqr(3)
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Similar expressions
- sqr(3x-1)+sqr(5x+8)+1=0
- x*3^(x-1)+3*3^sqr(3-x)=3^x+x*3^sqr(3-x)
- tg(x/3+pi/6)=sqr(3)
- sqr(7x+1)+sqr(3x-18)=sqr(2x+7)
tg(x/3-pi/6)=sqr(3) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
/x pi\ tan|- - --| = 9 \3 6 /
$$\tan{\left(\frac{x}{3} - \frac{\pi}{6} \right)} = 9$$
Rapid solution
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x1 = -pi - 3*acot(9)
$$x_{1} = - \pi - 3 \operatorname{acot}{\left(9 \right)}$$
x1 = -pi - 3*acot(9)
Sum and product of roots
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sum
-pi - 3*acot(9)
$$- \pi - 3 \operatorname{acot}{\left(9 \right)}$$
=
-pi - 3*acot(9)
$$- \pi - 3 \operatorname{acot}{\left(9 \right)}$$
product
-pi - 3*acot(9)
$$- \pi - 3 \operatorname{acot}{\left(9 \right)}$$
=
-pi - 3*acot(9)
$$- \pi - 3 \operatorname{acot}{\left(9 \right)}$$
-pi - 3*acot(9)
Numerical answer
[src]
x1 = -97.7213439248053
x2 = -31.7478981994196
x3 = 62.4998814082742
x4 = 34.225547525966
x5 = -88.2965659640359
x6 = 100.198993251352
x7 = -60.0222320817278
x8 = 5.9512136436579
x9 = 71.9246593690436
x9 = 71.9246593690436