Mister Exam
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How to use it?
- Equation:
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Equation x^3+4*x^2-x-4=0
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Equation cos(x)=3
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Equation x^4+x^2-20=0
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Equation 10(2-x)+11x=-3x
- Express {x} in terms of y where:
- 16*x-17*y=-9
- 20*x+13*y=1
- -19*x+1*y=0
- 9*x+17*y=13
- Derivative of:
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-3x
- Graphing y =:
- -3x
- Integral of d{x}:
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-3x
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Identical expressions
- ten (two -x)+11x=-3x
- 10(2 minus x) plus 11x equally minus 3x
- ten (two minus x) plus 11x equally minus 3x
- 102-x+11x=-3x
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Similar expressions
- x^4-5(x^3)-3(x^2)+13x+10=0
- sqrt(16-x^2)*(x^2-3*x-10)=0
- 10(2+x)+11x=-3x
- 10(2-x)-11x=-3x
- 10(2-x)+11x=+3x
10(2-x)+11x=-3x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$x = - 3 x - 20$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = -20$$
Divide both parts of the equation by 4
We get the answer: x = -5
10*(2-x)+11*x = -3*x
Expand brackets in the left part
10*2-10*x+11*x = -3*x
Looking for similar summands in the left part:
20 + x = -3*x
Move free summands (without x)
from left part to right part, we given:
$$x = - 3 x - 20$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = -20$$
Divide both parts of the equation by 4
x = -20 / (4)
We get the answer: x = -5
The graph