Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation (x-11)/(x-6)=11/16
-
Equation x^2-4x+6=0
-
Equation 5*x=12
-
Equation 2*sin(x)*cos(x)=0
- Express {x} in terms of y where:
- -20*x-7*y=-17
- -16*x-9*y=-5
- -8*x-11*y=1
- -20*x-18*y=20
-
Identical expressions
- ten - three (five x- fifteen)= two ,5-5x
- 10 minus 3(5x minus 15) equally 2,5 minus 5x
- ten minus three (five x minus fifteen) equally two ,5 minus 5x
- 10-35x-15=2,5-5x
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Similar expressions
- 10+3(5x-15)=2,5-5x
- 10-3(5x+15)=2,5-5x
- 10-3(5x-15)=2,5+5x
10-3(5x-15)=2,5-5x equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
10 - 3*(5*x - 15) = 5/2 - 5*x
$$10 - 3 \left(5 x - 15\right) = \frac{5}{2} - 5 x$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 15 x = - 5 x - \frac{105}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-10\right) x = - \frac{105}{2}$$
Divide both parts of the equation by -10
We get the answer: x = 21/4
10-3*(5*x-15) = (5/2)-5*x
Expand brackets in the left part
10-3*5*x+3*15 = (5/2)-5*x
Expand brackets in the right part
10-3*5*x+3*15 = 5/2-5*x
Looking for similar summands in the left part:
55 - 15*x = 5/2-5*x
Move free summands (without x)
from left part to right part, we given:
$$- 15 x = - 5 x - \frac{105}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-10\right) x = - \frac{105}{2}$$
Divide both parts of the equation by -10
x = -105/2 / (-10)
We get the answer: x = 21/4
Sum and product of roots
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sum
21/4
$$\frac{21}{4}$$
=
21/4
$$\frac{21}{4}$$
product
21/4
$$\frac{21}{4}$$
=
21/4
$$\frac{21}{4}$$
21/4