10/x−6/x+8=0 equation
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The solution
Detail solution
Given the equation:
$$\left(- \frac{6}{x} + \frac{10}{x}\right) + 8 = 0$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 1
b1 = 1/8
a2 = 1
b2 = -x/4
so we get the equation
$$- \frac{x}{4} = \frac{1}{8}$$
$$- \frac{x}{4} = \frac{1}{8}$$
Divide both parts of the equation by -1/4
x = 1/8 / (-1/4)
We get the answer: x = -1/2
$$x_{1} = - \frac{1}{2}$$
Sum and product of roots
[src]
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$