Mister Exam
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How to use it?
- Equation:
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Equation x^2+5*x-14=0
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Equation (x^2+9)/x=2*x
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Equation 3x^2+12x=0
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Equation (2-x)^2-x(x+1,5)=4
- Express {x} in terms of y where:
- -14*x-10*y=2
- -16*x-4*y=14
- -19*x-9*y=17
- -19*x-7*y=-12
- Graphing y =:
- 5-2x
- Integral of d{x}:
- 5-2x
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Identical expressions
- five -2x= one
- 5 minus 2x equally 1
- five minus 2x equally one
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Similar expressions
- 1^3*sqrt(5-2*x)=sqrt(3-x)
- (sqrt(5)+2)^x+1=2*(sqrt(5)-2)^x+1-1
- 5+2x=1
- 5*log(x/10)/log(10)=25-2*x/1000
5-2x=1 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = -4$$
Divide both parts of the equation by -2
We get the answer: x = 2
5-2*x = 1
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = -4$$
Divide both parts of the equation by -2
x = -4 / (-2)
We get the answer: x = 2
The graph