10/(6-x)=4/(x+2) equation
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The solution
Detail solution
Given the equation:
$$\frac{10}{6 - x} = \frac{4}{x + 2}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 10
b1 = 6 - x
a2 = 4
b2 = 2 + x
so we get the equation
$$10 \left(x + 2\right) = 4 \left(6 - x\right)$$
$$10 x + 20 = 24 - 4 x$$
Move free summands (without x)
from left part to right part, we given:
$$10 x = 4 - 4 x$$
Move the summands with the unknown x
from the right part to the left part:
$$14 x = 4$$
Divide both parts of the equation by 14
x = 4 / (14)
We get the answer: x = 2/7
Sum and product of roots
[src]
$$\frac{2}{7}$$
$$\frac{2}{7}$$
$$\frac{2}{7}$$
$$\frac{2}{7}$$