sqrt(x)=4 equation
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The solution
Detail solution
Given the equation
$$\sqrt{x} = 4$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{1 x + 0}\right)^{2} = 4^{2}$$
or
$$x = 16$$
We get the answer: x = 16
The final answer:
$$x_{1} = 16$$
Sum and product of roots
[src]
$$0 + 16$$
$$16$$
$$1 \cdot 16$$
$$16$$