Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 3^x=7
- Equation x-y=5
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Equation 3^x=2
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Equation 5x^2=0
- Express {x} in terms of y where:
- 1*x+6*y=-6
- -5*x+6*y=-8
- 7*x-6*y=-2
- 6*x+7*y=-10
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Identical expressions
- sqrt(three *x+ three)/ two = three
- square root of (3 multiply by x plus 3) divide by 2 equally 3
- square root of (three multiply by x plus three) divide by two equally three
- √(3*x+3)/2=3
- sqrt(3x+3)/2=3
- sqrt3x+3/2=3
- sqrt(3*x+3) divide by 2=3
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Similar expressions
- sqrt(3*x-3)/2=3
sqrt(3*x+3)/2=3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$\frac{\sqrt{3 x + 3}}{2} = 3$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\frac{\left(\sqrt{3 x + 3}\right)^{2}}{4} = 3^{2}$$
or
$$\frac{3 x}{4} + \frac{3}{4} = 9$$
Move free summands (without x)
from left part to right part, we given:
$$\frac{3 x}{4} = \frac{33}{4}$$
Divide both parts of the equation by 3/4
We get the answer: x = 11
The final answer:
$$x_{1} = 11$$
$$\frac{\sqrt{3 x + 3}}{2} = 3$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\frac{\left(\sqrt{3 x + 3}\right)^{2}}{4} = 3^{2}$$
or
$$\frac{3 x}{4} + \frac{3}{4} = 9$$
Move free summands (without x)
from left part to right part, we given:
$$\frac{3 x}{4} = \frac{33}{4}$$
Divide both parts of the equation by 3/4
x = 33/4 / (3/4)
We get the answer: x = 11
The final answer:
$$x_{1} = 11$$