Mister Exam
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How to use it?
- Equation:
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Equation log(x)=0
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Identical expressions
- sqrt(thirteen -2x)= six
- square root of (13 minus 2x) equally 6
- square root of (thirteen minus 2x) equally six
- √(13-2x)=6
- sqrt13-2x=6
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Similar expressions
- sqrt(13+2x)=6
sqrt(13-2x)=6 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$\sqrt{13 - 2 x} = 6$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{13 - 2 x}\right)^{2} = 6^{2}$$
or
$$13 - 2 x = 36$$
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = 23$$
Divide both parts of the equation by -2
We get the answer: x = -23/2
The final answer:
$$x_{1} = - \frac{23}{2}$$
$$\sqrt{13 - 2 x} = 6$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{13 - 2 x}\right)^{2} = 6^{2}$$
or
$$13 - 2 x = 36$$
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = 23$$
Divide both parts of the equation by -2
x = 23 / (-2)
We get the answer: x = -23/2
The final answer:
$$x_{1} = - \frac{23}{2}$$
Sum and product of roots
[src]
sum
-23/2
$$- \frac{23}{2}$$
=
-23/2
$$- \frac{23}{2}$$
product
-23/2
$$- \frac{23}{2}$$
=
-23/2
$$- \frac{23}{2}$$
-23/2