Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 12-(4-x)^2=x(3-x)
-
Equation 3^x=-3
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Equation x^2-7*x+5=0
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Equation x^2+4*x-21=0
- Express {x} in terms of y where:
- -11*x-14*y=6
- -17*x+9*y=-18
- 15*x+6*y=16
- 16*x-1*y=17
- Derivative of:
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sqrt5x
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Identical expressions
- sqrt5x= two * one / two *x
- square root of 5x equally 2 multiply by 1 divide by 2 multiply by x
- square root of 5x equally two multiply by one divide by two multiply by x
- √5x=2*1/2*x
- sqrt5x=21/2x
- sqrt5x=2*1 divide by 2*x
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Similar expressions
- ((2+(3)^(1/2))^(1/2))^(x)+((2-(3)^(1/2))^(1/2))^(x)=2^x
- (2/5)*x+(-x-(9/5))=-2*((1/2)*x-(3/10))
- 8*sqrt(5*x)+9=0
- sqrt(5*x-4)-sqrt(x+3)=1
- 53/4-(12/5-21/2x)=217/20
- sqrt(5x-1)=x-5
- sqrt(2*x-5)+sqrt(5x-6)=5
- 53/4-(13/5+21/2x)=217/20
sqrt5x=2*1/2*x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$\sqrt{5 x} = \frac{2}{2} x$$
Obviously:
next,
transform
$$\sqrt{x} = \sqrt{5}$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{x}\right)^{2} = \left(\sqrt{5}\right)^{2}$$
or
$$x = 5$$
We get the answer: x = 5
The final answer:
$$x_{1} = 5$$
$$\sqrt{5 x} = \frac{2}{2} x$$
Obviously:
x0 = 0
next,
transform
$$\sqrt{x} = \sqrt{5}$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{x}\right)^{2} = \left(\sqrt{5}\right)^{2}$$
or
$$x = 5$$
We get the answer: x = 5
The final answer:
x0 = 0
$$x_{1} = 5$$