Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2=-3
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Equation x^4=(2x-3)^2
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Equation 2*x^2+5*x-12=0
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Equation (x-87)-27=36
- Express {x} in terms of y where:
- 18*x+17*y=-14
- 16*x-17*y=-15
- -4*x-4*y=19
- 15*x+1*y=19
- Integral of d{x}:
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sqrt(3x+1)
- Derivative of:
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sqrt(3x+1)
- Graphing y =:
- sqrt(3x+1)
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Identical expressions
- sqrt(3x+ one)= four
- square root of (3x plus 1) equally 4
- square root of (3x plus one) equally four
- √(3x+1)=4
- sqrt3x+1=4
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Similar expressions
- sqrt3x+1=-9
- sqrt3-x=sqrt3x+1
- sqrt(3*x+15)=0
- sqrt(3x-1)=4
sqrt(3x+1)=4 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$\sqrt{3 x + 1} = 4$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{3 x + 1}\right)^{2} = 4^{2}$$
or
$$3 x + 1 = 16$$
Move free summands (without x)
from left part to right part, we given:
$$3 x = 15$$
Divide both parts of the equation by 3
We get the answer: x = 5
The final answer:
$$x_{1} = 5$$
$$\sqrt{3 x + 1} = 4$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{3 x + 1}\right)^{2} = 4^{2}$$
or
$$3 x + 1 = 16$$
Move free summands (without x)
from left part to right part, we given:
$$3 x = 15$$
Divide both parts of the equation by 3
x = 15 / (3)
We get the answer: x = 5
The final answer:
$$x_{1} = 5$$