Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation -7x=4
-
Equation x^2-6=0
- Equation x^2-x-90=0
-
Equation x^2+7*x+12=0
- Express {x} in terms of y where:
- -6*x-11*y=-20
- -15*x+7*y=1
- -1*x-20*y=1
- -1*x-15*y=13
- Integral of d{x}:
-
sqrt(3x+1)
- Derivative of:
-
sqrt(3x+1)
- Graphing y =:
- sqrt(3x+1)
-
Identical expressions
- sqrt(3x+ one)= four
- square root of (3x plus 1) equally 4
- square root of (3x plus one) equally four
- √(3x+1)=4
- sqrt3x+1=4
-
Similar expressions
- sqrt(x)^2-4*x-12+sqrt(3*x)+12=0
- sqrt(3x-1)=4
- sqrt(3*x+15)=0
- sqrt3x+1=-9
sqrt(3x+1)=4 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$\sqrt{3 x + 1} = 4$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{3 x + 1}\right)^{2} = 4^{2}$$
or
$$3 x + 1 = 16$$
Move free summands (without x)
from left part to right part, we given:
$$3 x = 15$$
Divide both parts of the equation by 3
We get the answer: x = 5
The final answer:
$$x_{1} = 5$$
$$\sqrt{3 x + 1} = 4$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{3 x + 1}\right)^{2} = 4^{2}$$
or
$$3 x + 1 = 16$$
Move free summands (without x)
from left part to right part, we given:
$$3 x = 15$$
Divide both parts of the equation by 3
x = 15 / (3)
We get the answer: x = 5
The final answer:
$$x_{1} = 5$$