Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation 2x+1-20x+15=6x+4
- Equation (x-1)^2·(2·x+6)+(x+3)^2·(2·x-2)=0
- Equation x^2-(1400*0.799)^2-x*(5.22*0.799)^2=0
- Equation x^2+25*x+1260=0
- Express {x} in terms of y where:
- 2*x-3*y=12
- -13*x-3*y=-2
- 15*x-6*y=-10
- 16*x-13*y=14
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Identical expressions
- six (x+ four)= seven (3x- two)
- 6(x plus 4) equally 7(3x minus 2)
- six (x plus four) equally seven (3x minus two)
- 6x+4=73x-2
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Similar expressions
- 6(x-4)=7(3x-2)
- 6(x+4)=7(3x+2)
- −4x−19=6x+41.
- (x-1)*(x^2+8*x+16)=6*(x+4)
- 2x+1-20x+15=6x+4
- 6x+4=8*(x-1)
- 7*3x-2=7*33x+9
6(x+4)=7(3x-2) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$6 x = 21 x - 38$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-15\right) x = -38$$
Divide both parts of the equation by -15
We get the answer: x = 38/15
6*(x+4) = 7*(3*x-2)
Expand brackets in the left part
6*x+6*4 = 7*(3*x-2)
Expand brackets in the right part
6*x+6*4 = 7*3*x-7*2
Move free summands (without x)
from left part to right part, we given:
$$6 x = 21 x - 38$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-15\right) x = -38$$
Divide both parts of the equation by -15
x = -38 / (-15)
We get the answer: x = 38/15
Sum and product of roots
[src]
sum
38 -- 15
$$\frac{38}{15}$$
=
38 -- 15
$$\frac{38}{15}$$
product
38 -- 15
$$\frac{38}{15}$$
=
38 -- 15
$$\frac{38}{15}$$
38/15