Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2x+1-20x+15=6x+4
- Equation (x-1)^2·(2·x+6)+(x+3)^2·(2·x-2)=0
- Equation x^2-(1400*0.799)^2-x*(5.22*0.799)^2=0
- Equation x^2+25*x+1260=0
- Express {x} in terms of y where:
- 2*x-3*y=12
- -13*x-3*y=-2
- 15*x-6*y=-10
- 16*x-13*y=14
- Integral of d{x}:
- 6x+4
- 8*(x-1)
- Graphing y =:
- 6x+4
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Identical expressions
- 6x+ four = eight *(x- one)
- 6x plus 4 equally 8 multiply by (x minus 1)
- 6x plus four equally eight multiply by (x minus one)
- 6x+4=8(x-1)
- 6x+4=8x-1
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Similar expressions
- 3*x^4+12*x^3-10*x^2-108*x-153=0
- 4*x^2-8x-140=0
- 6x-4=8*(x-1)
- 2,8x-10=-0,6x+18
- 6(x+4)=7(3x-2)
- 6x+4=8*(x+1)
- (x-1)*(x^2+8*x+16)=6*(x+4)
- (x+3)^4+3*x^2+18*x-1=0
6x+4=8*(x-1) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$6 x = 8 x - 12$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-2\right) x = -12$$
Divide both parts of the equation by -2
We get the answer: x = 6
6*x+4 = 8*(x-1)
Expand brackets in the right part
6*x+4 = 8*x-8*1
Move free summands (without x)
from left part to right part, we given:
$$6 x = 8 x - 12$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-2\right) x = -12$$
Divide both parts of the equation by -2
x = -12 / (-2)
We get the answer: x = 6