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6(x-3)+2(x+2)=1

6(x-3)+2(x+2)=1 equation

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Numerical solution:

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The solution

You have entered [src]
6*(x - 3) + 2*(x + 2) = 1
$$6 \left(x - 3\right) + 2 \left(x + 2\right) = 1$$
Detail solution
Given the linear equation:
6*(x-3)+2*(x+2) = 1

Expand brackets in the left part
6*x-6*3+2*x+2*2 = 1

Looking for similar summands in the left part:
-14 + 8*x = 1

Move free summands (without x)
from left part to right part, we given:
$$8 x = 15$$
Divide both parts of the equation by 8
x = 15 / (8)

We get the answer: x = 15/8
The graph
Rapid solution [src]
x1 = 15/8
$$x_{1} = \frac{15}{8}$$
x1 = 15/8
Sum and product of roots [src]
sum
15/8
$$\frac{15}{8}$$
=
15/8
$$\frac{15}{8}$$
product
15/8
$$\frac{15}{8}$$
=
15/8
$$\frac{15}{8}$$
15/8
Numerical answer [src]
x1 = 1.875
x1 = 1.875
The graph
6(x-3)+2(x+2)=1 equation