6(x-3)+2(x+2)=1 equation
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The solution
Detail solution
Given the linear equation:
6*(x-3)+2*(x+2) = 1
Expand brackets in the left part
6*x-6*3+2*x+2*2 = 1
Looking for similar summands in the left part:
-14 + 8*x = 1
Move free summands (without x)
from left part to right part, we given:
$$8 x = 15$$
Divide both parts of the equation by 8
x = 15 / (8)
We get the answer: x = 15/8
Sum and product of roots
[src]
$$\frac{15}{8}$$
$$\frac{15}{8}$$
$$\frac{15}{8}$$
$$\frac{15}{8}$$