Mister Exam
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- Equation:
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Equation 1/x^2-1/x-6=0
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Equation x^2-8=0
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Equation x^2=-3
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Equation x^4-2*x^3+x^2-1=0
- Express {x} in terms of y where:
- -9*x-12*y=-19
- 6*x+7*y=-10
- 4*x-11*y=-2
- -5*x-2*y=-14
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Identical expressions
- six /(x+ eight)=- three / four
- 6 divide by (x plus 8) equally minus 3 divide by 4
- six divide by (x plus eight) equally minus three divide by four
- 6/x+8=-3/4
- 6 divide by (x+8)=-3 divide by 4
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Similar expressions
- 6/(x-8)=-3/4
- 10/x−6/x+8=0
- ((3+5x)/(7x+4))-(3/4)=0
- 16/x+16/x+8/3=1
- (-2x-3)/(4+5x)=(7+4x)/(11-10x)
- 6/(x+8)=+3/4
- 6/x+8/y=7.2/x+9.6/y
6/(x+8)=-3/4 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{6}{x + 8} = - \frac{3}{4}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
so we get the equation
$$\frac{\left(-4\right) 6}{3} = x + 8$$
$$-8 = x + 8$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x + 16$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 16$$
Divide both parts of the equation by -1
We get the answer: x = -16
$$\frac{6}{x + 8} = - \frac{3}{4}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 6
b1 = 8 + x
a2 = 1
b2 = -4/3
so we get the equation
$$\frac{\left(-4\right) 6}{3} = x + 8$$
$$-8 = x + 8$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x + 16$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 16$$
Divide both parts of the equation by -1
x = 16 / (-1)
We get the answer: x = -16
The graph