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6(2x-1)-5(4-3x)=-80

6(2x-1)-5(4-3x)=-80 equation

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Numerical solution:

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The solution

You have entered [src]
6*(2*x - 1) - 5*(4 - 3*x) = -80
$$- 5 \left(4 - 3 x\right) + 6 \left(2 x - 1\right) = -80$$
Detail solution
Given the linear equation:
6*(2*x-1)-5*(4-3*x) = -80

Expand brackets in the left part
6*2*x-6*1-5*4+5*3*x = -80

Looking for similar summands in the left part:
-26 + 27*x = -80

Move free summands (without x)
from left part to right part, we given:
$$27 x = -54$$
Divide both parts of the equation by 27
x = -54 / (27)

We get the answer: x = -2
The graph
Rapid solution [src]
x1 = -2
$$x_{1} = -2$$
x1 = -2
Sum and product of roots [src]
sum
-2
$$-2$$
=
-2
$$-2$$
product
-2
$$-2$$
=
-2
$$-2$$
-2
Numerical answer [src]
x1 = -2.0
x1 = -2.0
The graph
6(2x-1)-5(4-3x)=-80 equation