6(2x-1)-5(4-3x)=-80 equation
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The solution
Detail solution
Given the linear equation:
6*(2*x-1)-5*(4-3*x) = -80
Expand brackets in the left part
6*2*x-6*1-5*4+5*3*x = -80
Looking for similar summands in the left part:
-26 + 27*x = -80
Move free summands (without x)
from left part to right part, we given:
$$27 x = -54$$
Divide both parts of the equation by 27
x = -54 / (27)
We get the answer: x = -2
Sum and product of roots
[src]
$$-2$$
$$-2$$
$$-2$$
$$-2$$