Mister Exam
其他计算器
-
如何使用？
- 方程:
-
方程 -x^2-4*x-3=0
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方程 3x+3=-2-7x
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方程 sin(-x)=0
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方程 (x+3)^3=81*(x+3)
- 在方程中将 {x} 用 y 表示:
- -5*x+9*y=0
- 16*x+2*y=14
- 18*x-1*y=6
- 19*x-9*y=8
- 导数:
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sin(x)
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10
- 积分 d{x}:
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sin(x)
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10
- 标准形:
- sin(x)
- 级数和:
-
10
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等价表达式
- sin(x)= ten
- 正弦 (x) 等于 10
- 正弦 (x) 等于 ten
- sinx=10
-
相似表达式
- sinx=10
sin(x)=10 方程
有了正确解答，你会成为小组里最受欢迎的人❤️😊
解答
Detail solution
Given the equation
$$\sin{\left(x \right)} = 10$$
- this is the simplest trigonometric equation
As right part of the equation
modulo =
but sin
can no be more than 1 or less than -1
so the solution of the equation d'not exist.
$$\sin{\left(x \right)} = 10$$
- this is the simplest trigonometric equation
As right part of the equation
modulo =
True
but sin
can no be more than 1 or less than -1
so the solution of the equation d'not exist.
Rapid solution
[src]
x1 = pi - re(asin(10)) - I*im(asin(10))
$$x_{1} = - \operatorname{re}{\left(\operatorname{asin}{\left(10 \right)}\right)} + \pi - i \operatorname{im}{\left(\operatorname{asin}{\left(10 \right)}\right)}$$
x2 = I*im(asin(10)) + re(asin(10))
$$x_{2} = \operatorname{re}{\left(\operatorname{asin}{\left(10 \right)}\right)} + i \operatorname{im}{\left(\operatorname{asin}{\left(10 \right)}\right)}$$
x2 = re(asin(10)) + i*im(asin(10))
Sum and product of roots
[src]
sum
pi - re(asin(10)) - I*im(asin(10)) + I*im(asin(10)) + re(asin(10))
$$\left(\operatorname{re}{\left(\operatorname{asin}{\left(10 \right)}\right)} + i \operatorname{im}{\left(\operatorname{asin}{\left(10 \right)}\right)}\right) + \left(- \operatorname{re}{\left(\operatorname{asin}{\left(10 \right)}\right)} + \pi - i \operatorname{im}{\left(\operatorname{asin}{\left(10 \right)}\right)}\right)$$
=
pi
$$\pi$$
product
(pi - re(asin(10)) - I*im(asin(10)))*(I*im(asin(10)) + re(asin(10)))
$$\left(\operatorname{re}{\left(\operatorname{asin}{\left(10 \right)}\right)} + i \operatorname{im}{\left(\operatorname{asin}{\left(10 \right)}\right)}\right) \left(- \operatorname{re}{\left(\operatorname{asin}{\left(10 \right)}\right)} + \pi - i \operatorname{im}{\left(\operatorname{asin}{\left(10 \right)}\right)}\right)$$
=
-(I*im(asin(10)) + re(asin(10)))*(-pi + I*im(asin(10)) + re(asin(10)))
$$- \left(\operatorname{re}{\left(\operatorname{asin}{\left(10 \right)}\right)} + i \operatorname{im}{\left(\operatorname{asin}{\left(10 \right)}\right)}\right) \left(- \pi + \operatorname{re}{\left(\operatorname{asin}{\left(10 \right)}\right)} + i \operatorname{im}{\left(\operatorname{asin}{\left(10 \right)}\right)}\right)$$
-(i*im(asin(10)) + re(asin(10)))*(-pi + i*im(asin(10)) + re(asin(10)))
Numerical answer
[src]
x1 = 1.5707963267949 + 2.99322284612638*i
x2 = 1.5707963267949 - 2.99322284612638*i
x2 = 1.5707963267949 - 2.99322284612638*i
图像