Mister Exam
Other calculators
-
How to use it?
- Equation:
- Equation x-y=7
-
Equation 1/(x+6)=2
-
Equation (x-4)^2-x^2=0
-
Equation 6/(x+5)=-5
- Express {x} in terms of y where:
- 7*x-1*y=-7
- 10*x-15*y=16
- -14*x-12*y=5
- 13*x-12*y=19
-
Identical expressions
- seven (x- one)= six - two (three -14x)
- 7(x minus 1) equally 6 minus 2(3 minus 14x)
- seven (x minus one) equally six minus two (three minus 14x)
- 7x-1=6-23-14x
-
Similar expressions
- 7(x-1)=6-2(3+14x)
- 7(x+1)=6-2(3-14x)
- 7(x-1)=6+2(3-14x)
- -4x^2+7x-1=0
- 8cos(x)+7sin(7x)-16x=(x^3)+8
- x^4=(7x-18)^2
- (2*x^2-7*x-15)*(2*sin(x)-sqrt(3))=0
7(x-1)=6-2(3-14x) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
7*(x - 1) = 6 - 2*(3 - 14*x)
$$7 \left(x - 1\right) = 6 - 2 \left(3 - 14 x\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$7 x = 28 x + 7$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-21\right) x = 7$$
Divide both parts of the equation by -21
We get the answer: x = -1/3
7*(x-1) = 6-2*(3-14*x)
Expand brackets in the left part
7*x-7*1 = 6-2*(3-14*x)
Expand brackets in the right part
7*x-7*1 = 6-2*3+2*14*x
Looking for similar summands in the right part:
-7 + 7*x = 28*x
Move free summands (without x)
from left part to right part, we given:
$$7 x = 28 x + 7$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-21\right) x = 7$$
Divide both parts of the equation by -21
x = 7 / (-21)
We get the answer: x = -1/3
Sum and product of roots
[src]
sum
-1/3
$$- \frac{1}{3}$$
=
-1/3
$$- \frac{1}{3}$$
product
-1/3
$$- \frac{1}{3}$$
=
-1/3
$$- \frac{1}{3}$$
-1/3