7^(x-2)=6 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$7^{x - 2} = 6$$
or
$$7^{x - 2} - 6 = 0$$
or
$$\frac{7^{x}}{49} = 6$$
or
$$7^{x} = 294$$
- this is the simplest exponential equation
Do replacement
$$v = 7^{x}$$
we get
$$v - 294 = 0$$
or
$$v - 294 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 294$$
We get the answer: v = 294
do backward replacement
$$7^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(7 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(294 \right)}}{\log{\left(7 \right)}} = \frac{\log{\left(294 \right)}}{\log{\left(7 \right)}}$$
Sum and product of roots
[src]
$$\frac{\log{\left(294 \right)}}{\log{\left(7 \right)}}$$
$$\frac{\log{\left(294 \right)}}{\log{\left(7 \right)}}$$
$$\frac{\log{\left(294 \right)}}{\log{\left(7 \right)}}$$
$$\frac{\log{\left(294 \right)}}{\log{\left(7 \right)}}$$
log(294)
x1 = --------
log(7)
$$x_{1} = \frac{\log{\left(294 \right)}}{\log{\left(7 \right)}}$$