7^x-2=49 equation
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The solution
Detail solution
Given the equation:
$$7^{x} - 2 = 49$$
or
$$\left(7^{x} - 2\right) - 49 = 0$$
or
$$7^{x} = 51$$
or
$$7^{x} = 51$$
- this is the simplest exponential equation
Do replacement
$$v = 7^{x}$$
we get
$$v - 51 = 0$$
or
$$v - 51 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 51$$
We get the answer: v = 51
do backward replacement
$$7^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(7 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(51 \right)}}{\log{\left(7 \right)}} = \frac{\log{\left(51 \right)}}{\log{\left(7 \right)}}$$
Sum and product of roots
[src]
$$\frac{\log{\left(51 \right)}}{\log{\left(7 \right)}}$$
$$\frac{\log{\left(51 \right)}}{\log{\left(7 \right)}}$$
$$\frac{\log{\left(51 \right)}}{\log{\left(7 \right)}}$$
$$\frac{\log{\left(51 \right)}}{\log{\left(7 \right)}}$$
log(51)
x1 = -------
log(7)
$$x_{1} = \frac{\log{\left(51 \right)}}{\log{\left(7 \right)}}$$