Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (x+2)^4-4*(x+2)^2-5=0
- Equation x-y=2
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Equation x^3+2x^2-x-2=0
- Equation (x+20)*(-x+10)=0
- Express {x} in terms of y where:
- 15*x+7*y=2
- 12*x-20*y=10
- -17*x-15*y=-17
- 6*x-2*y=20
- Integral of d{x}:
- -2*x-5
- Graphing y =:
- -2*x-5
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Identical expressions
- seven + eight *x=- two *x- five
- 7 plus 8 multiply by x equally minus 2 multiply by x minus 5
- seven plus eight multiply by x equally minus two multiply by x minus five
- 7+8x=-2x-5
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Similar expressions
- 7-8*x=-2*x-5
- -8*x^7+8*(x^4+x^7)=0
- 7x-(2x-5)=2(2x+3)
- x-3x-2/53-2x-5/3
- 17-3(15-x)=(4-x)-2(x-5)
- 7+8*x=-2*x+5
- 3x^4+5x^3−2x^2+x–7+8x^3−6x^2–3=0
- 7+8*x=+2*x-5
- (7+8x)-(13-x)-(6x-10,6)=-5
7+8*x=-2*x-5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$8 x = - 2 x - 12$$
Move the summands with the unknown x
from the right part to the left part:
$$10 x = -12$$
Divide both parts of the equation by 10
We get the answer: x = -6/5
7+8*x = -2*x-5
Move free summands (without x)
from left part to right part, we given:
$$8 x = - 2 x - 12$$
Move the summands with the unknown x
from the right part to the left part:
$$10 x = -12$$
Divide both parts of the equation by 10
x = -12 / (10)
We get the answer: x = -6/5
Sum and product of roots
[src]
sum
-6/5
$$- \frac{6}{5}$$
=
-6/5
$$- \frac{6}{5}$$
product
-6/5
$$- \frac{6}{5}$$
=
-6/5
$$- \frac{6}{5}$$
-6/5
The graph