Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation (x+2)^4-4*(x+2)^2-5=0
- Equation x-y=2
-
Equation x^3+2x^2-x-2=0
- Equation (x+20)*(-x+10)=0
- Express {x} in terms of y where:
- 15*x+7*y=2
- 12*x-20*y=10
- -17*x-15*y=-17
- 6*x-2*y=20
-
Identical expressions
- 7x-(two x- five)=2(2x+ three)
- 7x minus (2x minus 5) equally 2(2x plus 3)
- 7x minus (two x minus five) equally 2(2x plus three)
- 7x-2x-5=22x+3
-
Similar expressions
- 7x-(2x-5)=2(2x-3)
- (5*x-1)*(x+2)+3*(x-4)*(x+4)=2*(2*x+3)^2-8
- 7x+(2x-5)=2(2x+3)
- log(2)^2*(x)+3*(Abs((log(x)/log(2))))+2=0
- 7x-(2x+5)=2(2x+3)
- 9^x+1-43×2^2x+3+6^3-x=0
7x-(2x-5)=2(2x+3) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
7*x + -2*x + 5 = 2*(2*x + 3)
$$7 x + \left(5 - 2 x\right) = 2 \left(2 x + 3\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$5 x = 4 x + 1$$
Move the summands with the unknown x
from the right part to the left part:
$$x = 1$$
We get the answer: x = 1
7*x-(2*x-5) = 2*(2*x+3)
Expand brackets in the left part
7*x-2*x+5 = 2*(2*x+3)
Expand brackets in the right part
7*x-2*x+5 = 2*2*x+2*3
Looking for similar summands in the left part:
5 + 5*x = 2*2*x+2*3
Move free summands (without x)
from left part to right part, we given:
$$5 x = 4 x + 1$$
Move the summands with the unknown x
from the right part to the left part:
$$x = 1$$
We get the answer: x = 1