Mister Exam
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How to use it?
- Equation:
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Equation 2x=4
-
Equation x^2=x+72
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Equation 7/(x-5)=2
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Equation x^2-11*x+18=0
- Express {x} in terms of y where:
- 11*x+3*y=-16
- -2*x+13*y=-6
- 20*x-3*y=3
- 18*x-7*y=-4
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Identical expressions
- seven /(x- five)= two
- 7 divide by (x minus 5) equally 2
- seven divide by (x minus five) equally two
- 7/x-5=2
- 7 divide by (x-5)=2
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Similar expressions
- (x^2+9*x+7)/((x-5)^2*(x+1)^2)=-(3/((x-5)*(x+1)))
- 7/(x+5)=2
7/(x-5)=2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{7}{x - 5} = 2$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
so we get the equation
$$\frac{7}{2} = x - 5$$
$$\frac{7}{2} = x - 5$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x - \frac{17}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = - \frac{17}{2}$$
Divide both parts of the equation by -1
We get the answer: x = 17/2
$$\frac{7}{x - 5} = 2$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 7
b1 = -5 + x
a2 = 1
b2 = 1/2
so we get the equation
$$\frac{7}{2} = x - 5$$
$$\frac{7}{2} = x - 5$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x - \frac{17}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = - \frac{17}{2}$$
Divide both parts of the equation by -1
x = -17/2 / (-1)
We get the answer: x = 17/2
Sum and product of roots
[src]
sum
17/2
$$\frac{17}{2}$$
=
17/2
$$\frac{17}{2}$$
product
17/2
$$\frac{17}{2}$$
=
17/2
$$\frac{17}{2}$$
17/2
The graph