Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 10/(6-x)=4/(x+2)
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Equation 13-6(5x-2)=4
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Equation x-4/2+3*x=5
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Equation sin(x)=5/2
- Express {x} in terms of y where:
- -9*x-20*y=19
- -12*x-18*y=-16
- -11*x+17*y=-17
- -16*x-16*y=12
- Graphing y =:
- 2(x+1)
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Identical expressions
- one (x- four)= two (x+ one)
- 1(x minus 4) equally 2(x plus 1)
- one (x minus four) equally two (x plus one)
- 1x-4=2x+1
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Similar expressions
- 1(x+4)=2(x+1)
- (x+2)(x-3)(x+1)(x-4)+4=0
- abs(x+abs(2x+1))=8
- -3(2,1x-4)-4,2=1,2(-5x+0,5)
- -2x+1+5*(x-2)=-4*(3-x)+1
- 9*x^2-12*x+11=0
- (x+8)2-(2x-1)(x-4)=60
- 12x+15=3x-12
- √(2x+1)-√(x-3)=√x
- 1(x-4)=2(x-1)
- (x-1)(x-4)+2=0
1(x-4)=2(x+1) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$x = 2 x + 6$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 6$$
Divide both parts of the equation by -1
We get the answer: x = -6
1*(x-4) = 2*(x+1)
Expand brackets in the left part
1*x-1*4 = 2*(x+1)
Expand brackets in the right part
1*x-1*4 = 2*x+2*1
Move free summands (without x)
from left part to right part, we given:
$$x = 2 x + 6$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 6$$
Divide both parts of the equation by -1
x = 6 / (-1)
We get the answer: x = -6