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1-x/2-2(3-4x)-6,5(x-1)=2x equation

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Numerical solution:

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The solution

You have entered [src] 
    x                 13*(x - 1)      
1 - - - 2*(3 - 4*x) - ---------- = 2*x
    2                     2
$$- \frac{13 \left(x - 1\right)}{2} + \left(- 2 \left(3 - 4 x\right) + \left(- \frac{x}{2} + 1\right)\right) = 2 x$$
Simplify
Detail solution
Given the linear equation:
1-x/2-2*(3-4*x)-(13/2)*(x-1) = 2*x

Expand brackets in the left part
1-x/2-2*3+2*4*x-13/2x-1 = 2*x

Looking for similar summands in the left part:
3/2 + x = 2*x

Move free summands (without x)
from left part to right part, we given:
$$x = 2 x - \frac{3}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = - \frac{3}{2}$$
Divide both parts of the equation by -1
x = -3/2 / (-1)

We get the answer: x = 3/2
The graph
Plot the graph f1(x)
Plot the graph f2(x)
Sum and product of roots [src] 
sum
3/2
$$\frac{3}{2}$$ 
=
3/2
$$\frac{3}{2}$$ 
product
3/2
$$\frac{3}{2}$$ 
=
3/2
$$\frac{3}{2}$$ 
3/2
Rapid solution [src] 
x1 = 3/2
$$x_{1} = \frac{3}{2}$$ 
x1 = 3/2
Numerical answer [src] 
x1 = 1.5
x1 = 1.5
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